Question

㏒₂(ײ+3×)=2 помогитееее

Answer 1

$log_{2}( {x}^{2} + 3x) = 2 \\ {x}^{2} + 3x = 4 \\ {x}^{2} + 3x - 4 = 0 \\ (x + 4)(x - 1) = 0 \\ x = - 4 \\ x = 1 \\ {x}^{2} + 3x > 0 \\ x(x + 3) > 0 \\ x = 1 \\ x = - 4$