Question

допоможітььь!!!!!!!!!!!!!

Answer 1

$(3 \sqrt{6} + 2 \sqrt{8} - \sqrt{32} ) \sqrt{2} - \sqrt{108} = (3 \sqrt{6} + 4 \sqrt{2} - 4 \sqrt{2} ) \sqrt{2} - 6 \sqrt{3} = 3 \sqrt{12} - 6 \sqrt{3} = 6 \sqrt{3} - 6 \sqrt{3} = 0$