Question

помогите решить пажалусто

Answer 1

2 ctg(5п/4) + sqr(3) tg(-5п/3) = ?

Отдельно:
ctg(5п/4) = cos(5п/4) / sin(5п/4) = [ - sqr(2)/2] / [ - sqr(2)/2] = 1
tg(-5п/3) = sin(-5п/3) / cos(-5п/3) = [ sqr(3)/2] / [ 1/2] = sqr(3)

2 ctg(5п/4) + sqr(3) tg(-5п/3) = 2 + sqr(3) sqr(3) = 2 + 3 = 5