Question

помогите доказать равновесие

Answer 1

(1-4sin²αcos²α)/(sinα+cosα)²-2cosαsin(-α)=1
(1-(2sinαcosα)²/(sin²α+2sinαcosα+cos²α)+2sinαcosα=1
(1-sin²2α)/(1+sin2α)+sin2α=1
cos²2α/(1+sin2α)+sin2α=1
(cos²2α+sin2α+sin²2α)/(1+sin2α)=1
(1+sin2α)/(1+sin2α)=1
1≡1.