Question

а^-4а+4 дробь а^+6а+9 * 2а^-18 дробь 12-6

Answer 1

(a^2-4а+4)/(а^2+6а+9) * (2а^2-18)/(12-6a)=(a-2)^2/(a+3)^2*2(a^2-9)/6(2-a)=(a-2)^2*2(a-3)(a+3)/(a+3)^2*6*(2-a)=-(a-2)(a-3)/3(a+3)=(-1/3)*[(a-2)(a-3)/(a+3)]