Question

пожалуйста, решите этот логарифм

Answer 1

$(5log_{96} 2 + log_{96} 3) * (4log_{27} \sqrt{9} -log_{27} 3) = \\ \\ = (log_{96} 2^5 + log_{96} 3) * (log_{27} (\sqrt{9})^4 -log_{27} 3) = \\ \\ = (log_{96} 32 + log_{96} 3) * (log_{27} 81 - log_{27} 3) = \\ \\ = (log_{96} (32 * 3) ) * (log_{27} (81 : 3) ) = log_{96} 96 * log_{27} 27 = 1 * 1 = 1$