Question

Выразите log24 132 через a и b если log12 6=a, log12 11=b

Answer 1

log24(132) = log12(132) / log12(24) = log12(12*11) / log12(144/6) =

= (  log12(12) + log12(11) )  / ( log12(144) - log12(6) ) =

= ( 1 + b )  / ( log12(12^2) - a ) = ( 1 + b )  / ( 2 log12(12) - a ) =

= ( 1 + b )  / ( 2 - a )