Question

3a(a+1)+(a^2+1) помогите решить пжжж

Answer 1

3a*(a+1)+(a²+1)=3a²+3a+a²+1=4a²+3a+1

Answer 2

$3a(a + 1) + (a ^{2} + 1) = 3a {}^{2} + 3a + a {}^{2} + 1 = 4a {}^{2} + 3a + 1$
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