Question

log12 6=a , log12 11=b log24 132=? Напишите ответ через а,b

Answer 1

$log_{24}132=\frac{log_{12}122}{log_{12}24}=\frac{log_{12}12+log_{12}11}{log_{12}144-log_{12}6}=\frac{1+b}{2-a}$