Question

Помогите пожалуйста,только по подробнее!!!!!

Answer 1

$\frac{x-4}{x+4} *(x+ \frac{ x^{2} }{4-x} )= \frac{x-4}{x+4}* \frac{4x- x^{2} + x^{2} }{4-x} = -\frac{(x-4)*4x}{(x+4)(x-4)} =- \frac{4x}{x+4}$

Answer 2

$\frac{x-4}{x+4} * (x+\frac{x^2}{4-x})$ = $\frac{x-4}{x+4} * \frac{(x *(4-x)+x^2}{4-x}$ = $\frac{x-4}{x+4} * \frac{4x<strong>-x^2+x^2</strong>}{4-x}$ = $\frac{x-4}{x+4} * \frac{4x<strong></strong>}{4-x}$ = $\frac<strong>{x-4}</strong>{x+4} * -\frac{4x<strong></strong>}<strong>{x-4}</strong>$ = - $\frac<strong></strong>{x+4}{4x<strong></strong>}<strong></strong>$