Question

Решите оба, пожалуйста

Answer 1

(1/5)^3x+4:(1/5)^-5x-2=1/125
(1/5)^3x+4:(1/5)^-5x-2=1/125
(1/5)^8x+6=5^-3
5^-(8x+6)=5^-3
5^-8x-6=^-3
-8x-6=-3
-8x-6=-3+6
-8x=3
x=-3/8

(1/4)^5x+2:(1/4)^3x+4=1/64
(1/64)^5x+2:(1/4)^3x+4=1/64
(1/4)^2x-2=2^-6
2^-4x+4=2^-6
-4x+4=-6
-4x=-6-4
-4x=-10
x=2,5

Answer 2

$( \frac{1}{5} )^{3x+4}:( \frac{1}{5} )^{-5x-2}= \frac{1}{125} \\ \\ ( \frac{1}{5} )^{3x+4-(-5x-2)}= \frac{1}{5^3} \\ \\ ( \frac{1}{5} )^{8x+6}= (\frac{1}{5})^3 \\ \\ 8x+6=3 \\ 8x=3-6 \\ 8x=-3 \\ x=- \frac{3}{8} \\ \\ \\ ( \frac{1}{4} )^{5x+2}:( \frac{1}{4} )^{3x+4}= \frac{1}{64} \\\\ ( \frac{1}{4} )^{5x+2-(3x+4)}= \frac{1}{4^3}\\\\ ( \frac{1}{4} )^{2x-2}= (\frac{1}{4})^3 \\ \\ 2x-2=3 \\ 2x=3+2 \\ 2x=5 \\ x=2.5$