Question

Если logx 1/9 = 2, то х =

Answer 1

$log_{x} \frac{1}{9}=2 \\ \\ log_{x} \frac{1}{9}=log_{x}x^2 \\ \\ x^2= \frac{1}{9} \\ x= \frac{1}{3}$

Answer 2

logx (1/9)=2        ОДЗ:  x∈(0;1)U(1;+∞)
x²=1/9
x²-1/9=0
x²-(1/3)²=0
(x-1/3)*(x+1/3)=0
x₁=1/3     x₂=-1/3 ∉ОДЗ.
Ответ: x=1/3.