Question

найдите производную функции
y=(2+3)*1/x

Answer 1

$y' = \frac{(2+3x)'}{x} +(2+3x) (\frac{1}{x} )'= \frac{3}{x} - \frac{2+3x}{x^2} = \frac{3x-2-3x}{x^2} =- \frac{2}{x^2}$