Question

найдите корень уравнения √4+x+√x=4

Answer 1

$\sqrt{4+x} + \sqrt{x} = 4\\ x \geq 0\\ 4 + x + 2\sqrt{x^2+4x} +x = 16 \\ 2\sqrt{x^2+4x} = -2x + 12 \\ \sqrt{x^2+4x}= 6-x \\ x^2 + 4x = 36 - 12x + x^2 \\ 16x = 36 \\ x = 2,25$