Question

Помогите, пожалуйста, решить

Answer 1

1) 5x - 16 ≥ 0                    2)  16 - x² ≠ 0
    5x ≥ 16                               x² - 16 ≠ 0
    x ≥ 3,2                                (x - 4)(x + 4) ≠ 0                                                
                                                x ≠ 4    x ≠ - 4
                                                 ////////////////////////////////////////////////
__________₀________________________₀___________                 
                   - 4                         3,2                 4

Область определения :  x ∈ [3,2 ; 4) ∪ (4 , + ∞)

Answer 2

Решение задания приложено