Question

1/2log корень из 21 9+log21 49
log6 5*log5 8+log6 27

Answer 1

$\frac{1}{2}log_{ \sqrt{21} } 9+log_{21}49= log_{ \sqrt{21} } \sqrt{9} +log_{21}49 =log_{21}9+log_{21}49=$$log_{21}9*49 = log_{21}441 = log_{21}21^2=2*log_{21}21=2*1=2$


$log_65*log_58+log_627 = log_65* \frac{log_68}{log_65}+log_627=log_68+log_627=$$log_68*27=log_6216=log_66^3=3*1=3$