Question

Помогите пожалуйста со 2 и 5 заданием

Answer 1

2. 2sin (5x+π/3)=√2
sin (5x+π/3)=√2/2
5x+π/3=π/4+2πk, k целое       5x+π/3=3π/4+2πk, k целое
5x=-π/12+2πk, k целое             5x=5π/12+2πk, k целое
x=-π/60+2πk/5,  k целое            x=π/12+2πk/5, k целое

5. cos (2x-π/3)<1/2
π/3+2πk <2x-π/3<5π/3+2πk, k целое
2π/3+2πk <2x <2π+2πk, k целое
π/3+πk <x <π+πk, k целое