Question

Упростите выражение √242х + √162х - √32х

Answer 1

$\sqrt{242} x+ \sqrt{162}x- \sqrt{32}x= \\ \\ \sqrt{121*2}x+ \sqrt{81*2}x- \sqrt{16*2}x= \\ \\ = \sqrt{121} \sqrt{2} x+ \sqrt{81} \sqrt{2} x- \sqrt{16} \sqrt{2} x= \\ \\ =11 \sqrt{2}x+9 \sqrt{2}x-4 \sqrt{2}x= \\ \\ =(11+9-4) \sqrt{2}x=16 \sqrt{2}x$