Question

Помогите пожалуйста.

Answer 1

$\frac{c-3}{c}-\frac{c^2-9}{c}*\frac{1}{c-3}=\frac{c-3}{c}-\frac{c^2-9}{c*(c-3)}=\\\\ =\frac{c-3}{c}-\frac{(c-3)*(c+3)}{c*(c-3)}=\frac{c-3}{c}-\frac{c+3}{c}=\\\\ =\frac{c-3-(c+3)}{c}=\frac{c-3-c-3}{c}=\frac{-6}{c}=-\frac{6}{c}$



$\frac{(y^3)^4*y^2}{y^7}=\frac{y^{3*4}*y^2}{y^7}=\frac{y^{12}*y^2}{y^7}=\frac{y^{14}}{y^7}=\frac{y^7*y^7}{y^7}=y^7$