Question

X2-y2/2xy * 2y/x-y решите

Answer 1

$\frac{x^2-y^2}{2xy} * \frac{2y}{x-y} = \frac{(x-y)(x+y) * 2y}{2y*x*(x-y)} = \frac{1*(x+y)*1}{1*x*1} = \frac{x+y}{x} = \\ \\ = \frac{1}{x} (x+y) = 1+ \frac{y}{x}$