Question

$\f \frac{1}{3}$(6x-y)=-3
-2(x-3y)=20
Решите систему уравнений

Answer 1

$\left \{ {{ \frac{1}{3} (6x-y)=-3} \atop {-2(x-3y)=20}} \right.$
$\left \{ {{2x- \frac{y}{3}=-3 } \atop {-2x+6y=20}} \right.$
$6y- \frac{y}{3} =17$
$18y-y=51$
$17y =51$
$y = 3$
$-2x+18 =20$
$-2x = 2$
$x=-1$