Question

решите пж не понимаю

Answer 1

$\frac{2x-3}{6}*42\ \textless \ \frac{4x+1}{7}*42\\\\7(2x-3)\ \textless \ 6(4x+1)\\\\14x-21\ \textless \ 24x+6\\\\14x-24x\ \textless \ 6+21\\\\-10x\ \textless \ 27\\\\x\ \textgreater \ -2,7$
x ∈ (- 2,7 ; + ∞)
Ответ : - 2