Question

Преобразуйте выражение:

Answer 1

$(1+ \frac{3x+x^2}{x+3} ):( \frac{1}{x+1}- \frac{x}{1+2x+x^2}) ^{-1}= \\ \\ (1+ \frac{x(x+3)}{x+3} ):( \frac{1}{x+1}- \frac{x}{(x+1)^2}) ^{-1}= \\ \\ (1+x):(\frac{x+1-x}{(x+1)^2})^{-1}=(1+x):(1+x)^2= \frac{1}{1+x}$