Question

Решите уравнение 8y-(3у+19)= -3(2у-1)

Answer 1

$8y-(3y+19)=-3(2y-1) \\8y-3y-19=-6y+3 \\5y-16=-6y+3 \\5y+6y=3+19 \\11y=22:11 \\y=2.$

Answer 2

8у - ( 3у + 19 ) = - 3( 2у - 1 )
8у - 3у - 19 = - 6у + 3
5у - 19 = - 6у + 3
5у + 6у = 19 + 3
11у = 22
у = 22 ÷ 11
у = 2.