Question

Помогите решить. Упростить выражение.

Answer 1

$\frac{a^2-1}{4a+8b} * \frac{a^2+4ab+4b^2}{3-3a} = \\ \\ \frac{(a-1)(a+1)}{4(a+2b)}* \frac{(a+2b)(a+2b)}{3(1-a)} =- \frac{a+1)(a+2b)}{12}$

Answer 2

a² - 1/4a + 8b * a² + 4ab + 4b²/3 - 3a

=(a - 1) * (a + 1)/4(a + 2b) * (a + 2b)²/- 3a+3

= (a - 1) * (a + 1)/4 * a + 2b/- 3(a - 1)

= a + 1/4 * a + 2b/ - 3

= - (a + 1) * (a + 2b)/12

= - a² + 2ab + a + 2b/12