Question

Решите уравнения( ^ - степень):
1)169х^3-26х^2+х=0
2)х^3-2х^2-25х+50=0

Answer 1

1)В первом уравнении один корень х=0.                                                       
  Сократив на х получим квадратное169х*х-26х+1=0                               
удобно 13х=у                                                                     
           у*у-2у+1=0                                                      
     у=1                                       
х=1/13                                                          
Два решения х=0 и х=1/13                                                  
2) сразу видим х=2                                                                   
Поделим на (х-2)                                                
х*х+ах-25=0                                                             
а=0                                                                 
х*х-25=0                                                             
х=5 или х=-5                                         
Ответ: х=2 или х=5 или х=-5