Question

log4(3x+1)=log4(2x−1)

Answer 1

$log_{4}(3x + 1) = log_{4}(2x - 1) \\ log_{4}(3x + 1) - log_{4}(2x - 1) = 0 \\ log_{4}( \frac{3x + 1}{2x - 1} ) = 0 \\ \frac{3x + 1}{2x - 1} = 4^{0} \\ \frac{3x + 1}{2x - 1} = 1 \\ 3x + 1 = 2x - 1 \\ x = - 2$