Question

Решите методом подстановки систему уравнений 2х + y = 3,

3x + 2y = 2.

Answer 1

Ответ:

(x; y)∈{(4; -5)}

Объяснение:

$\displaystyle \left \{ {{2*x+y=3} \atop {3*x+2*y=2}} \right. \\\\\left \{ {{y=3-2*x} \atop {3*x+2*(3-2*x)=2}} \right.\\\\\left \{ {{y=3-2*x} \atop {3*x+6-4*x=2}} \right.\\\\\left \{ {{y=3-2*x} \atop {-x=2-6}} \right.\\\\\left \{ {{y=3-2*x} \atop {-x=-4}} \right.\\\\\left \{ {{y=3-2*4=3-8=-5} \atop {x=4}} \right.$

Отсюда: (x; y)∈{(4; -5)}