Question

0,2*(-3x+5)+0,3x*(2-5x)+2,5x(2)=

-(0,1-(-0,02)+0,03-(-2,08))=

-(a+в)+(c-a)+2*(а+в-с)-(в+а)=

-(а+в-с)+а-(в+с)-в+3*(в+а)=

Answer 1

$1)0.2 \times ( - 3x) + 0.2 \times 5 + \\ 0.3x \times 2 - 0.3x \times 5x + 2.5 \times 2 =$
-0,6х+1+0,6х-1,5х+5=-1,5х+6
$2) - (0.1 - ( - 0.02) + 0.03 - \\ ( - 2.08) = - 0.12 + 2.11 = 1.99$
$3) - (a + b) + (c - a) \\ + 2(a + b - c) - (b + a)$
$- a - b + c - a + 2a + 2b - 2c \\ - b - a = - a - c$
$4) - a - b + c + a - b - c - b \\ + 3b + 3a = 3a$