Question

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(3x)^2/x^-25
x^-10/3x^8

Answer 1

$\frac{(3x)^2}{x^{- 25}} = (3^1x^1)^2 : \frac{1}{x^{25} }= 3^{1*2}*x^{1*2} * \frac{x^{25}}{1} = 3^2 *x^2 *x^{25} = 9x^{2+25}=9x^{27} \\ \\ \frac{x^{-10}}{3x^8} = \frac{1}{x^{10}} : 3x^8 = \frac{1}{x^{10}} * \frac{1}{3x^8} = \frac{1}{3x^{10+8}} = \frac{1}{3x^{18}}$