Question

Решите пожалуйста Алгебра

Answer 1

$S(t)= \frac{1}{4} t^{4} - t^{3}+2\\\\V(t) = S'(t) = \frac{1}{4}( t^{4} )'-( t^{3})'+2'= t^{3}-3 t^{2} \\\\a(t)=V'(t) = ( t^{3})' -3( t^{2})'=3 t^{2} -6t \\\\a(t)=0\\\\3 t^{2} -6t=0\\\\ t^{2}-2t=0\\\\t(t-2)=0\\\\ t_{1}=0\\\\t-2=0\\\\ t_{2}=2 \\\\ t\ \textgreater \ 0$
Ответ: 2