Question

раскройте скобки,только верно!
${ ({x}^{2} - x - 4)}^{2}$

Answer 1

$(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc$

$(x^2-x-4)^2=x^4+x^2+16-2x^3-8x^2+8x= \\= x^4-2x^3-7x^2+8x+16$

Answer 2

$\mathtt{(a+b+c)^2=a(a+b+c)+b(a+b+c)+c(a+b+c)=}\\\mathtt{a^2+ab+ac+ab+b^2+bc+ac+bc+c^2=}\\\mathtt{a^2+b^2+c^2+2ab+2bc+2ac}$

так, 

$\mathtt{(x^2-x-4)^2=}\\\mathtt{(x^2)^2+(-x)^2+(-4)^2+2x^2(-x)+2(-x)(-4)+2x^2(-4)=}\\\mathtt{x^4+x^2+16-2x^3+8x-8x^2=}\\\mathtt{x^4-2x^3-7x^2+8x+16}$