Question

Помогите решить уравнение.

Answer 1

$lgx=t \\ t^2+t-12=0 \\ \left \{ {{t_1=3} \atop {t_2=-4}} \right. \\ \left \{ {{lgx=3} \atop {lgx=-4}} \right. \\ \left \{ {{x=10^3} \atop {x=10^{-4}}} \right. \\ \left \{ {{x=1000} \atop {x= \frac{1}{10000} }} \right.$