Question

f(x) = x√2-x²

Нужно найти D(x)

Answer 1

$f(x)=x\sqrt{2-x^2}\\\\2-x^2 \geq 0\\\\x^2-2 \leq 0\\\\(x-\sqrt2)(x+\sqrt2)\\\\+++[\, \sqrt2\, ]---[\, \sqrt2\, ]+++\\\\x\in [-\sqrt2;\sqrt2\, ]$