Question

Помогите пожалуйста

Answer 1

$\mathtt{(\frac{7}{20})^{\frac{5}{\sqrt{x}}+3}=(\frac{20}{7})^{\frac{7}{\sqrt{x}}-5};~(\frac{7}{20})^{\frac{5\sqrt{x}+3x}{x}}=(\frac{20}{7})^{\frac{7\sqrt{x}-5x}{x}}=(\frac{7}{20})^{\frac{5x-7\sqrt{x}}{x}};~}\\\mathtt{\frac{5\sqrt{x}+3x}{x}=\frac{5x-7\sqrt{x}}{x};~\frac{12\sqrt{x}-2x}{x}=0;~6\sqrt{x}-x=0;~x^2-36x=0;~x=36}$