Question

Решите уравнение пж
(y-1)^2-(y-2)(y+2)=y-4

Answer 1

(y-1)^2-(y-2)(y+2)=y-4
y^2-2y+1-(y^2-2y+2y-4)=y-4
y^2-2y+1-y^2+2y-2y+4=y-4
-2y+5=y-4
-2y-y=-4-5
-3y=-9
y=3