Предмет: Математика, автор: Аноним

сторона ВС четырёхугольника АВСД равна 28 см что вдвое больше стороны АД сторона АВ на 9 см меньше ВС и на 3 см больше СД найдите  периметр четырёхугольника

Ответы

Автор ответа: galo4ka58
0
ВС=28
AD=14
AB=19
CD=16
периметр - сумма длин всех сторон. Р=28+14+19+16=77
Автор ответа: Аноним
0
ауу
Автор ответа: galo4ka58
0
"сторона АВ на 9 см меньше ВС и на 3 см больше СД"
Автор ответа: Аноним
0
19-3
Автор ответа: galo4ka58
0
ну да. 19-3
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