Question

Всем привет! Помогите решить систему неравенств:
$\left \{ {{1+\frac{2x+3}{3}\ \textless \ }\frac{x+1}{4} \atop {6(2x-1)+7\ \textless \ 5(x-4)}} \right.$

Answer 1

$\left \{ {{1*12+ \frac{2x+3}{3} *12\ \textless \ \frac{x+1}{4}*12 } \atop {12x-6+7\ \textless \ 5x-20}} \right.\\\\ \left \{ {{12+8x+12\ \textless \ 3x+3} \atop {12x+1\ \textless \ 5x-20}} \right.\\\\ \left \{ {{8x-3x\ \textless \ 3-24} \atop {12x-5x\ \textless \ -1-20}} \right.$
$\left \{ {{5x\ \textless \ -21} \atop {7x\ \textless \ -21}} \right.\\\\ \left \{ {{x\ \textless \ -4,2} \atop {x\ \textless \ -3}} \right.$
Ответ:x ∈ (-∞ ; - 4,2)