Question

Pomogite pj tererereree axaxa

Answer 1

a) $\frac{4y}{6x} * \frac{12x}{16y}= \frac{1}{1} * \frac{2}{4} = \frac{2}{4} = \frac{1}{2}$

б) $\frac{a^{2}-2a}{3a-a^{2}} : \frac{5a-10a}{6-2a}= \frac{a(a-2)}{a(3-a)} : \frac{-5a}{2(3-a)} = \frac{a-2}{3-a}* \frac{2(3-a)}{-5a}= \frac{-2(a-2)}{5a} = \frac{4-2a}{5a}$