Question

1
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√4x+3. >0 помогите пж, дам 34 балла !!!!

Answer 1

$\frac{1}{ \sqrt{4x+3} } \ \textgreater \ 0 \\ \\ 4x+3\ \textgreater \ 0 \\ x\ \textgreater \ - \frac{3}{4} \\ \\ x \in (- \frac{3}{4} ;+\infty)$