Question

Выполните задание,срочно

Answer 1

$x= \sqrt[3]{a} ;y= \sqrt[3]{b} \\ \\ \left \{ {{x+y=6} \atop {x^3+y^3=72}} \right. \\ \\ x^3+(6-x)^3=72 \\ \\ x^3+216-108x+18x^2-x^3=72 \\ \\ 18x^2-108x+144=0 \\ \\ x^2-6x+8=0 \\ \\ D=36-32=4 \\ \\ x=(6+2)/2=4;y=2 \\ \\ a=4^3=64;b=2^3=8 \\ \\ x=(6-2)/2=2;y=4 \\ \\ a=2^3=8;b=4^3=64 \\ \\ OTVET : (8;64)(64;8)$