Question

2в -17степени ×4в 6 ÷8в-3 степени

Answer 1

${2}^{ - 17} \times {4}^{6} \div {8}^{ - 3} = \frac{1}{ {2}^{17} } \times ( { {2}^{2} })^{6} \div ( { {2}^{3} })^{ - 3} = \frac{ {2}^{12} }{ {2}^{17} } \div {2}^{ - 9} = \frac{1}{ {2}^{5} } \div \frac{1}{ {2}^{9} } = \frac{1}{ {2}^{5} } \times \frac{ {2}^{9} }{1} = \frac{ {2}^{4} }{1} = 16$