Предмет: Математика, автор: nastyaageeva11

1) Из двух городов расстояние между которыми 840км,вышли одновременно навстречу друг другу 2 поезда.Скорость первого 100км/ч,а второго-на 10км/ч больше.Через сколько часов поезда встретятся?
2)Сравни величины
6700см...67дм
6700см...67м
89000мм...98м
3470мм...34дм 7см
17040м...17км 400м
8т 200кг...820ц
5580коп...5руб 58коп
48ч...3 сут
7т 320кг...732ц
PS:второе задание это больше,меньше,или равно,и можно быстрее?

Ответы

Автор ответа: Rada9mama5papa610

1 ) 100 + 10 =110 километров - скорость 2
2 ) 100 + 110 = 210 километров в час - скорость сближения
3 ) 840 : 210 = 4 часа - время
Ответ : через 4 часа они встретятся

1 ) =
2 ) =
3 ) -
4 ) -
5 ) - 6 ) - 7 = 8 ) - 9 =

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