Question

Решите Квадратное неравенство:4х^+3х-1<0

Answer 1

$4 x^{2} +3x-1 \ \textless \ 0\\ \\ 4 x^{2} +3x-1 = 0\\ \\ a=4;b=3;c=-1;\\ \\ D = b^{2} - 4ac = 9-4*4*(-1) = 9 + 16 = 25\\ \\ x_{1} = \frac{-3+ \sqrt{25}}{2*4}= \frac{2}{8} =\frac{1}{4} \\ \\ x_{2} = \frac{-3- \sqrt{25}}{2*4}= \frac{-8}{8} =-1$