Question

решите неравенство
${a}^{ {x}^{2} - x} < {a}^{2}$

Answer 1

$a^{x^2-x}\ \textless \ a^2 \\ x^2-x\ \textless \ 2 \\ x^2-x-2\ \textless \ 0 \\ D=1+8=3^2\\ x_1=(1+3)/2=2 \\ x_2=(1-3)/2=-1\\ \\ x \in (-1;2)$