Предмет: Алгебра,
автор: halisaaa
помогите решить 5 номер слева
Приложения:
![](https://files.topotvet.com/i/fe5/fe59f02265e7621aa35126385e8192b3.jpg)
Ответы
Автор ответа:
2
а)
![(\frac{b+1}{b-1}- \frac{b}{b+1} ): \frac{3b+1}{2b-2} \\
\\\frac{(b+1) ^{2}-b(b-1) }{(b-1)*(b+1)} * \frac{2b-2}{3b+1} \\ \\ \frac{(b+1)^{2}-b^{2}+b}{(b-1)*(b+1)} * \frac{2(b-1)}{3b+1} \\
\\ \frac{(b+1)^{2}-b^{2}+b}{(b-1)*(b+1)}* \frac{2(-1)}{3b+1}\\
\\ \frac{2((b+1)^{2}-b^{2}+b}{(b+1)*(3b+1)}\\
\\ \frac{2(b+1)^{2}-2b^{2}+2b}{(b+1)*(3b+1)} \\
\\ \frac{2((b+1)^{2}-b^{2}+b)}{(b+1)*(3b+1)}\\
\\ \frac{2(b^{2}+2b+1-b^{2}+b)}{(b+1)(3b+1)}\\
\\ \frac{2(3b+1)}{b+1)(3b+1)} \\
\\ \frac{2}{b+1} . (\frac{b+1}{b-1}- \frac{b}{b+1} ): \frac{3b+1}{2b-2} \\
\\\frac{(b+1) ^{2}-b(b-1) }{(b-1)*(b+1)} * \frac{2b-2}{3b+1} \\ \\ \frac{(b+1)^{2}-b^{2}+b}{(b-1)*(b+1)} * \frac{2(b-1)}{3b+1} \\
\\ \frac{(b+1)^{2}-b^{2}+b}{(b-1)*(b+1)}* \frac{2(-1)}{3b+1}\\
\\ \frac{2((b+1)^{2}-b^{2}+b}{(b+1)*(3b+1)}\\
\\ \frac{2(b+1)^{2}-2b^{2}+2b}{(b+1)*(3b+1)} \\
\\ \frac{2((b+1)^{2}-b^{2}+b)}{(b+1)*(3b+1)}\\
\\ \frac{2(b^{2}+2b+1-b^{2}+b)}{(b+1)(3b+1)}\\
\\ \frac{2(3b+1)}{b+1)(3b+1)} \\
\\ \frac{2}{b+1} .](https://tex.z-dn.net/?f=+%28%5Cfrac%7Bb%2B1%7D%7Bb-1%7D-+%5Cfrac%7Bb%7D%7Bb%2B1%7D+%29%3A+%5Cfrac%7B3b%2B1%7D%7B2b-2%7D++%5C%5C%0A%5C%5C%5Cfrac%7B%28b%2B1%29+%5E%7B2%7D-b%28b-1%29+%7D%7B%28b-1%29%2A%28b%2B1%29%7D+%2A+%5Cfrac%7B2b-2%7D%7B3b%2B1%7D+%5C%5C+%5C%5C+%5Cfrac%7B%28b%2B1%29%5E%7B2%7D-b%5E%7B2%7D%2Bb%7D%7B%28b-1%29%2A%28b%2B1%29%7D+%2A+%5Cfrac%7B2%28b-1%29%7D%7B3b%2B1%7D+%5C%5C%0A%5C%5C+%5Cfrac%7B%28b%2B1%29%5E%7B2%7D-b%5E%7B2%7D%2Bb%7D%7B%28b-1%29%2A%28b%2B1%29%7D%2A+%5Cfrac%7B2%28-1%29%7D%7B3b%2B1%7D%5C%5C%0A%5C%5C+%5Cfrac%7B2%28%28b%2B1%29%5E%7B2%7D-b%5E%7B2%7D%2Bb%7D%7B%28b%2B1%29%2A%283b%2B1%29%7D%5C%5C%0A%5C%5C++%5Cfrac%7B2%28b%2B1%29%5E%7B2%7D-2b%5E%7B2%7D%2B2b%7D%7B%28b%2B1%29%2A%283b%2B1%29%7D+%5C%5C%0A%5C%5C+%5Cfrac%7B2%28%28b%2B1%29%5E%7B2%7D-b%5E%7B2%7D%2Bb%29%7D%7B%28b%2B1%29%2A%283b%2B1%29%7D%5C%5C%0A%5C%5C++%5Cfrac%7B2%28b%5E%7B2%7D%2B2b%2B1-b%5E%7B2%7D%2Bb%29%7D%7B%28b%2B1%29%283b%2B1%29%7D%5C%5C%0A%5C%5C+%5Cfrac%7B2%283b%2B1%29%7D%7Bb%2B1%29%283b%2B1%29%7D++%5C%5C%0A%5C%5C+%5Cfrac%7B2%7D%7Bb%2B1%7D+.)
б)
![(\frac{c-2}{c+2}- \frac{c}{c-2})* \frac{c+2}{2-3c}\\
\\ \frac{(c-2)^{2}-c*(c+2)}{(c+2)*(c-2)} * \frac{c+2}{2-3c}\\
\\ \frac{(c-2)^{2}-c^{2}-2c}{c-2} * \frac{1}{2-3c} \\
\\ \frac{(c-2)^{2}-c^{2}-2c}{(c-2)*(2-3c)}\\
\\ \frac{c^{2}-4c+4-c^{2}-2c}{(c-2)*(2-3c)} \\
\\ \frac{-6c+4}{(c-2)*(2-3c)} \\
\\ \frac{2(-3c+2)}{(c-2)*(2-3c)} \\
\\ \frac{2}{c-2} (\frac{c-2}{c+2}- \frac{c}{c-2})* \frac{c+2}{2-3c}\\
\\ \frac{(c-2)^{2}-c*(c+2)}{(c+2)*(c-2)} * \frac{c+2}{2-3c}\\
\\ \frac{(c-2)^{2}-c^{2}-2c}{c-2} * \frac{1}{2-3c} \\
\\ \frac{(c-2)^{2}-c^{2}-2c}{(c-2)*(2-3c)}\\
\\ \frac{c^{2}-4c+4-c^{2}-2c}{(c-2)*(2-3c)} \\
\\ \frac{-6c+4}{(c-2)*(2-3c)} \\
\\ \frac{2(-3c+2)}{(c-2)*(2-3c)} \\
\\ \frac{2}{c-2}](https://tex.z-dn.net/?f=+%28%5Cfrac%7Bc-2%7D%7Bc%2B2%7D-+%5Cfrac%7Bc%7D%7Bc-2%7D%29%2A+%5Cfrac%7Bc%2B2%7D%7B2-3c%7D%5C%5C%0A%5C%5C+%5Cfrac%7B%28c-2%29%5E%7B2%7D-c%2A%28c%2B2%29%7D%7B%28c%2B2%29%2A%28c-2%29%7D+%2A+%5Cfrac%7Bc%2B2%7D%7B2-3c%7D%5C%5C%0A%5C%5C+%5Cfrac%7B%28c-2%29%5E%7B2%7D-c%5E%7B2%7D-2c%7D%7Bc-2%7D+%2A+%5Cfrac%7B1%7D%7B2-3c%7D++%5C%5C%0A%5C%5C+%5Cfrac%7B%28c-2%29%5E%7B2%7D-c%5E%7B2%7D-2c%7D%7B%28c-2%29%2A%282-3c%29%7D%5C%5C%0A%5C%5C+%5Cfrac%7Bc%5E%7B2%7D-4c%2B4-c%5E%7B2%7D-2c%7D%7B%28c-2%29%2A%282-3c%29%7D+%5C%5C%0A%5C%5C+%5Cfrac%7B-6c%2B4%7D%7B%28c-2%29%2A%282-3c%29%7D+%5C%5C%0A%5C%5C+%5Cfrac%7B2%28-3c%2B2%29%7D%7B%28c-2%29%2A%282-3c%29%7D+%5C%5C%0A%5C%5C+%5Cfrac%7B2%7D%7Bc-2%7D++++)
б)
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