Question

КТО РЕШИТ???6 ЗАДАНИЕ?)

Answer 1

6x + 3y - 26 = 3x - 2y
15 - x + 3y = 2x + 5

3x + 5y = 26
- 3x + 3y = - 10
------------------------- + 
8y = 16
y = 2

x = (26 - 5*y)/3 = 16/3

ОТВЕТ
(16/3; 2)

Answer 2

$\left \{ {{3(2x+y)-26=3x-2y} \atop {15-(x-3y)=2x+5}} \right. \; \left \{ {{6x+3y-26=3x-2y} \atop {15-x+3y=2x+5}} \right. \; \left \{ {{5y+3x=26} \atop {3y-3x=-10}} \right.\oplus \\\\ \left \{ {{5y+3x=26} \atop {8y=16}} \right. \left \{ {{5\cdot 2+3x=26} \atop {y=2}} \right. \; \left \{ {{3x=16} \atop {y=2}} \right.\; \left \{ {{x=\frac{16}{3}} \atop {y=2}} \right. \; \; \Rightarrow \; \; (5\frac{1}{3}\, ;\, 2)$