Question

помогите, пожалуйста с алгеброй

Answer 1

$\frac{x^2}{x^2+6xy} : \frac{x^2}{x^2-36y^2}= \frac{x^2}{x(x6+6y)} * \frac{(x-6y)(x+6y)}{x^2} = \frac{x-6y}{x} \\ \frac{4-6 \sqrt{6}-6(8- \sqrt{6}) }{4-6 \sqrt{6} } = \frac{4-6 \sqrt{6}-48+6 \sqrt{6} }{2(2-3 \sqrt{6}) } = \frac{-22}{2-3 \sqrt{6} }$

Answer 2

$\frac{ x^{2} }{ x^{2} +6xy}: \frac{x}{ x^{2} -36 y^{2} }= \frac{ x^{2} }{x(x+6y)}* \frac{ x^{2} -36 y^{2} }{x}= \frac{ x^{2} }{x(x+6y)}* \frac{(x-6y)(x+6y)}{x}=x-6y\\\\\\4-6 \sqrt{6}-6(8- \sqrt{6})=4-6 \sqrt{6}-48+6 \sqrt{6} =-44$