Question

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Answer 1

3) $(12\frac{307}{728} - 4,7 * 2 \frac{2}{7}) : (-4,85) = (\frac{9043}{728} - \frac{47}{10} * \frac{16}{7}) : (- \frac{97}{20}) =$$(\frac{9043}{728} - \frac{47}{5} * \frac{8}{7}) : (-\frac{97}{20}) = (\frac{9043}{728} - \frac{376}{35}) : (- \frac{97}{20}) =$$(\frac{45215}{3640} - \frac{39104}{3640}) : (- \frac{97}{20}) = \frac{6111}{3640} : (- \frac{97}{20}) = \frac{873}{520} * (- \frac{20}{97}) = - \frac{9}{520} * 20 = - \frac{9}{26}$
4) $5,4 * (- \frac{5}{18}) - (3 \frac{8}{11}) : (- \frac{5}{11}) - (-\frac{2}{5}) = \frac{27}{5} * (- \frac{5}{18}) - \frac{41}{11} * \frac{11}{5} + \frac{2}{5} =$$- \frac{3}{2} - \frac{41}{5} + \frac{2}{5} = - \frac{15}{10} - \frac{82}{10} + \frac{4}{10} = \frac{71}{10}$
5) $\frac{450,9704-48,828:9,75*90,05}{8 \frac{2}{5}- 4\frac{2}{7}*2\frac{1}{4}:8 \frac{3}{14}} = \frac{450,9704-5,008*90,05}{8 \frac{2}{5}- 4\frac{2}{7}*2\frac{1}{4}:8 \frac{3}{14}} =$$\frac{450,9704-450,9704}{8 \frac{2}{5}- 4\frac{2}{7}*2\frac{1}{4}:8 \frac{3}{14}} = \frac{0}{8 \frac{2}{5}- 4\frac{2}{7}*2\frac{1}{4}:8 \frac{3}{14}} = 0$