Question

доброй ночи.помогите пож.решить 6 класс

Answer 1

$\frac{12.1* \frac{18}{99}+4.2* \frac{3}{7} }{0.16( \frac{17}{12}- \frac{5}{13} )} = \frac{2.2+1.8}{ \frac{161}{975} } = \frac{4*975}{161} =24 \frac{36}{161}$

Answer 2

$\frac{12,1\cdot 0,(18)+4,2\, :\, 2\frac{1}{3}}{1\frac{5}{12}\cdot 0,16-\frac{5}{13}\cdot 0,16}=\frac{\frac{121}{10}\cdot \frac{18}{99}+\frac{42}{10}:\frac{7}{3}}{(\frac{17}{12}-\frac{5}{13})\cdot 0,16}=\frac{\frac{11\cdot 18}{10\cdot 9}+\frac{42\cdot 3}{10\cdot 7}}{\frac{161}{12\cdot 13}\cdot \frac{16}{100}}=\frac{\frac{11}{5}+\frac{9}{5}}{\frac{161}{975}}=\\\\=\frac{4\cdot 975}{161}=\frac{3900}{161}=24\frac{36}{161}$